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5x^2-6x-11=x^2-9x
We move all terms to the left:
5x^2-6x-11-(x^2-9x)=0
We get rid of parentheses
5x^2-x^2-6x+9x-11=0
We add all the numbers together, and all the variables
4x^2+3x-11=0
a = 4; b = 3; c = -11;
Δ = b2-4ac
Δ = 32-4·4·(-11)
Δ = 185
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-\sqrt{185}}{2*4}=\frac{-3-\sqrt{185}}{8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+\sqrt{185}}{2*4}=\frac{-3+\sqrt{185}}{8} $
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